Skip to main content

The $\operatorname{erf}$ function

Can a function be 'defined' as the anti-derivative of another function?

$\operatorname{erf}$ is one such function. Even though it has various proper infinite series expansions (as in Wolfram MathWorld - Erf), it is defined by mathematicians as such:
$$\operatorname{erf}(z) \equiv \frac{2}{\sqrt{\pi}}\int_0^ze^{-t^2}dt$$
This function has extensive implications in statistics, and can be used to express the integral of $e^{-x^2}$ and $e^{x^2}$. See the post that tries to find integral of $e^{x^2}$ - we need not use integration by parts there, but rather can use the $\operatorname{erf}$ function.

Source: Wolfram MathWorld

Comments

Popular posts from this blog

Factorials, and the Gamma Function

What is the Gamma function? What does it have to do with the factorial of a number? And why does such a formula even work? The Factorial In our high school combinatorics course, we were introduced to the factorial of a natural number. We defined the factorial of a number $n$ to be the product of all the natural numbers till $n$. Or symbolically: $$n! = 1 . 2 . 3 ... (n-2)  (n-1)  n$$ This is a very useful function in Counting problems. This function also pops up in the exponential function: $$e^x = 1+\frac{x}{1!}+\frac{x^2}{2!}+\frac{x^3}{3!}+...$$ Setting this aside, we think: can we 'extend' this function to all real number? Surely, even if we were to come up with such a function, what would it mean to take this new 'factorial' of some real number? Well, let's take a look at one important property of the factorial function: $$n! = n(n-1)!$$ and this is true for all natural numbers $n$. So, even if we came up with this homologous function, we...

Why does integration give the area under the curve?

The definite integral between two points $a$ and $b$ gives the area under the curve for the function between $a$ and $b$, textbooks say. A question arises - how? I had this doubt when I started to learn calculus in my school. And I decided to set out to prove it. Consider a function $\operatorname{f}$, and its derivative $\operatorname{f'}$. We have to prove that $\int_a^b \operatorname{f'}(x) = $ Area under the curve for $\operatorname{f'}(x)$ between $a$ and $b$ Let Area under the curve for $\operatorname{f'}(x)$ between $a$ and $b$ = $S$ Divide the shaded region into parts of very very small width $\delta \to 0$. Each part can be considered as a rectangle of width $\delta$ and height $\operatorname{f'}(c)$ where $c$ is the $x$ coordinate of the graph, $a\le c\le b$. $$\therefore S = \lim_{\delta \to 0}\Bigl(\delta \times \operatorname{f'}(a) + \delta \times \operatorname{f'}(a+\delta) + \delta \times \operatorname{f'}(a+2\delta) +...\\+ \...